更新sdk-fix

src/sdk-fix.js

 /**
  * 检测传入的XPath是否有表的存在，如果没有返回null
- * @param {string[]} absolutePaths Xpath绝对路径集合
- * @returns {object} 返回对象信息
+ * @param {object[]} tags 元素集合{xpath=XPath,name=返回的属性名,title=标题信息,type=操作类型：文本，链接，元素路径（点击动作用）,relativePath=相对路径（最终的）}
+ * @returns {any} 返回对象信息{}
  */
-function checkTableFromXpaths(absolutePaths) {
+function checkTableFromXpaths(tags) {
     let rtns = null;
     //先找到共同的根以及各路径在共同根下的相对路径
-    let parent = getCommonParentXPath(absolutePaths);
+    let parent = getCommonParentXPath(tags);
     if (parent == null || parent.length == 0) return rtns;//如果找不到直接返回null
     let relativeXpaths = getRelativeXPaths(parent, absolutePaths);//根据相同的根找到绝对路径的相对路径
     while (parent.length > 0) {
@@ -14,6 +14,8 @@ function checkTableFromXpaths(absolutePaths) {
         parent.pop();//向上一级找
         relativeXpaths = getRelativeXPaths(parent, absolutePaths);//重新获取相对路径
     }
+    if (parent.length === 0) return rtns;//如果父对象都为空了，直接返回null
+    let tableData = getTableData(parent, relativeXpaths);//根据验证后的信息来获取表
     rtns = {
         parent: parent,
         relativeXpaths: relativeXpaths,
@@ -26,17 +28,14 @@ function checkTableFromXpaths(absolutePaths) {
  * @param {string[]} absolutePaths Xpath绝对路径集合
  * @returns {string[]} 返回string[]的共同的根的各部分的集合
  */
-function getCommonParentXPath(absolutePaths) {
+function getCommonParentXPath(tags) {
     let rtns = null;
-    if (!absolutePaths || absolutePaths.length === 0) {
-        return rtns;
-    }
-    let splitPaths = absolutePaths.map(path => path.split('/'));// 分割每个路径为组成部分
+    if (!tags || tags.length === 0) return rtns;
+    let allXpaths = tags.map(path => tag.xpath.split('/'));// 分割每个路径为组成部分
     rtns = [];// 查找公共前缀
-    for (let i = 0; i < splitPaths[0].length; i++) {
-        let currentPart = splitPaths[0][i];
-        if (splitPaths.every(path => path[i] === currentPart)) { // 检查所有路径是否有这个部分
-            rtns.push(currentPart);
+    for (let i = 0; i < allXpaths[0].length; i++) {
+        if (allXpaths.every(path => path[i] === allXpaths[0][i])) { // 检查所有路径是否有这个部分
+            rtns.push(allXpaths[0][i]);
         } else {break;}//如果发现不同的，直接就可以退出了
     }
     return rtns;